Question

Can someone please help me with the question in the picture part (c)​

Answer 1

Answer:

from left right triangle

sin theta = c/a

cos theta = b/a

tan theta = c/b

from right triangle (right side)

sin theta = d/e

cos theta = c/e

tan theta = d/c

from big right triangle

sin theta = e/(b+d)

cos theta = a/(b+d/

tan theta = e/a