Can someone please help me with the question in the picture part (c)
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Answer:
from left right triangle
sin theta = c/a
cos theta = b/a
tan theta = c/b
from right triangle (right side)
sin theta = d/e
cos theta = c/e
tan theta = d/c
from big right triangle
sin theta = e/(b+d)
cos theta = a/(b+d/
tan theta = e/a
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