can someone please solve 10th one
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Udita34:
hello
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[(x²)^{1/3)]^(1/4),
[x^(2/3)]^(1/4)],
then
x^(2/3×1/4),
x^(2/12),
x^(1/6)
[x^(2/3)]^(1/4)],
then
x^(2/3×1/4),
x^(2/12),
x^(1/6)
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