dear brainly friends, please do help me with this sum . i will be so thankful to you.
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meenakshi997sa:
ans is 130???
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hope it helps you...
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In this Figure.. First We Join AD to BC.
and Lets Mark it as AM.
Now angle M(inside of AMB)=180°-(<A+<B)
=180°-80°=100°
Now In ∆DMC
<M=180-100°=80°
Now unsing the proof that The Sum of opposite interior angles = External Angle...
x=<M+<C
→X=80°+50°=130°
Hope it helps....
and Lets Mark it as AM.
Now angle M(inside of AMB)=180°-(<A+<B)
=180°-80°=100°
Now In ∆DMC
<M=180-100°=80°
Now unsing the proof that The Sum of opposite interior angles = External Angle...
x=<M+<C
→X=80°+50°=130°
Hope it helps....
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