Can someone please solve this question
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KrishMatrix:
Please do it in pen and paper
soory yrr time nahi hai
hope u dont mind
that r u not getting in that
Okay np
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in the given triangle we now that line jioning center to point of contact is 90 to tangent.
now using ASP in triangle Adb
so D=40
now OD=OC radii
so DCO=40
so using asp now DOC=100
now by liear pair COA=80
now using ASP in triangle Adb
so D=40
now OD=OC radii
so DCO=40
so using asp now DOC=100
now by liear pair COA=80
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