Question

can someone share preboard paper of sst class 10 cbse board

Answer 1

x^2-3*x-8-(2)=0 The first term is,  x2  its coefficient is  1 .

The middle term is,  -3x  its coefficient is  -3 .

The last term, "the constant", is  -10 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -10 = -10 

Step-2 : Find two factors of  -10  whose sum equals the coefficient of the middle term, which is   -3 .

     -10   +   1   =   -9     -5   +   2   =   -3   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -5  and  2 

                     x2 - 5x + 2x - 10

Step-4 : Add up the first 2 terms, pulling out like factors :