can someone solve my physics assignment
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Q1
when velocity changes at non uniform rate it is defined by the ratio of total displacement/ total time and when velocity changes at uniform rate it is given by the sum of initial +final velocity/2=u+v/2
Q2
DISTANCE=1384km
time=5 hrs
avg speed=d/t
=1384/5
=276.8km/hr
Q3
case1 s=30 km/hr
t=30 min=1/2hr
d=s*t=30*1/2=15 km
case2=s=25 km/hr
t=1 hr
d=s*t=25*1=25 km
case3=s=40 km/hr
t=2 hrs
d=s *t=40*2=80 km/hr
now..............
avg speed=total distance/total time
=15+25+80/ 7/2
=120/7*2
=17.1*2
=34.2 km/hr
Q4
TOTAL DISTANCE=120 km
case1 =d1=30 km
s1=30 km/hr
t1=d/s=1 hr
avg speed =total distance/total time taken
60=120/t1+t2
60t2=120-60=60
t2=60/60=1 hrs
d2=90 km /hr
t2=1 hr
s2=d/t=90/1=90 km/hr
Q5
U=0.5 m/s
a= --0.05 m/s^2
v=0 m/s
by using 1st eq. of motion
v=u+at
0=0.5-0.05t(a is negative)
-0.5=-0.05t
cancelling minus sign and 0.5 by 0.05
t=10s
Q7
Motion of MOON around EARTH is accelerated because although the speeds is uniform but velocity is not as the direction is changing continuously.
Q8
Speed remains constant in circular motion
Q9
Direction changes continuously
Q10
v=0 m/s
t=25 s
a= -1.5 m/s^2
u=?
v=u+at
0=u-1.5*25
-u=-37.5
u=37.5 m/s
Q11
SPEEDOMETER
Q12
RETARDATION or DECCELERATION
Q13
POSITIVE ACCELERATION --If the acceleration is in the direction of velocity it is positive
NEGATIVE ACCELERATION--If the acceleration is in opposite direction of velocity it is negative
Q14
a=v-u/t
=m/s-m/s/s
=m/s/s
=m/s^2
hence derived ,si unit of acceleration =m/s^2
Q15
D=100 m
t=5 min=300s
avg speed=total distance/total time taken
=100/300
=1/3 m/s
now.........
1/3 m/s=1/3*18/5 km/hr
=6/5 km/hr=1.2 km/hr
when velocity changes at non uniform rate it is defined by the ratio of total displacement/ total time and when velocity changes at uniform rate it is given by the sum of initial +final velocity/2=u+v/2
Q2
DISTANCE=1384km
time=5 hrs
avg speed=d/t
=1384/5
=276.8km/hr
Q3
case1 s=30 km/hr
t=30 min=1/2hr
d=s*t=30*1/2=15 km
case2=s=25 km/hr
t=1 hr
d=s*t=25*1=25 km
case3=s=40 km/hr
t=2 hrs
d=s *t=40*2=80 km/hr
now..............
avg speed=total distance/total time
=15+25+80/ 7/2
=120/7*2
=17.1*2
=34.2 km/hr
Q4
TOTAL DISTANCE=120 km
case1 =d1=30 km
s1=30 km/hr
t1=d/s=1 hr
avg speed =total distance/total time taken
60=120/t1+t2
60t2=120-60=60
t2=60/60=1 hrs
d2=90 km /hr
t2=1 hr
s2=d/t=90/1=90 km/hr
Q5
U=0.5 m/s
a= --0.05 m/s^2
v=0 m/s
by using 1st eq. of motion
v=u+at
0=0.5-0.05t(a is negative)
-0.5=-0.05t
cancelling minus sign and 0.5 by 0.05
t=10s
Q7
Motion of MOON around EARTH is accelerated because although the speeds is uniform but velocity is not as the direction is changing continuously.
Q8
Speed remains constant in circular motion
Q9
Direction changes continuously
Q10
v=0 m/s
t=25 s
a= -1.5 m/s^2
u=?
v=u+at
0=u-1.5*25
-u=-37.5
u=37.5 m/s
Q11
SPEEDOMETER
Q12
RETARDATION or DECCELERATION
Q13
POSITIVE ACCELERATION --If the acceleration is in the direction of velocity it is positive
NEGATIVE ACCELERATION--If the acceleration is in opposite direction of velocity it is negative
Q14
a=v-u/t
=m/s-m/s/s
=m/s/s
=m/s^2
hence derived ,si unit of acceleration =m/s^2
Q15
D=100 m
t=5 min=300s
avg speed=total distance/total time taken
=100/300
=1/3 m/s
now.........
1/3 m/s=1/3*18/5 km/hr
=6/5 km/hr=1.2 km/hr
RohanSachdeva:
its 4 pm to 9am the next day that means t= 17hr in 2 ques
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