Question

can someone solve part a for me please?

Answer 1

height of equilateral triangle (h)=(√3/2)a
given height=9
$( \frac{ \sqrt{3} }{2} ) \times a = 9$
$a = \frac{9 \times 2}{ \sqrt{3} }$a=18/√3
a=[18/√3]×(√3/√3)
a=18√3/3
a=6√3
length of each side=6×1.732=10.393cms
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