Question

Can someone solve question 11 and 12. Please and thank you.

Answer 1

Answer

11. $17 sin50\textdegree tan40\textdegree$ m

12. $75(tan60\textdegree - tan50\textdegree )$ m

Q11.

→ $\overline{AC}=17sin50\textdegree$

→ $\overline{BC}=tan40\textdegree\overline{AC}$

→ $\overline{BC}=17 sin50\textdegree tan40\textdegree$

Q12.

→ $\overline{AC}=75 tan(90-30) \textdegree=75 tan60 \textdegree$

→ $\overline{CD}=75 tan(90-40) \textdegree=75 tan50 \textdegree$

→ $\overline{AD} = \overline{AC} - \overline{CD}$

→ $\overline{AD} =75 (tan60 \textdegree - tan50 \textdegree )$