Can someone solve this integral???
(cos^4 x + sin^4 x) /(cos^2x - sin^2x)
Attachments:
Answers
Answered by
3
Answer:
Use the identities:
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
)
cos
2
x
+
sin
2
x
=
1
sin
4
x
−
cos
4
x
=
(
sin
2
x
−
cos
2
x
)
(
sin
2
x
+
cos
2
x
)
=
sin
2
x
−
cos
2
x
Answered by
1
Answer:
Use the identities:
a2−b2=(a−b)(a+b))
cos2x+sin2x=1
sin4x−cos4x=(sin2x−cos2x)(sin2x+cos2x)
=sin2x−cos2x
Step-by-step explanation:
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