can someone solve this question
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Sn= 3n+8 / 7n+15
make it into 2 separate parts as there are 2 different ap's :-
find A12 of first ap and then of the other.
first one:-
sn= 3n+8
s(1)= 3+8=11
s(2)= 3(2)+8=14
s(3)= 3(3)+8=17 so AP= 11, 14, 17.....
a=11 , d= 14-11=3
A12= a+(n-1)d
= 11+(12-1)3 = 11+33 = 44.
now a12 of other AP:-
sn=7n+15
s(1)= 22
s(2)= 7(2)+15= 29
s(3)= 21+ 15= 36 so AP= 22,29,36.....
a=22, d=7
A12= a+(n-1)d
= 22+(12-1)7 = 22+77 = 99
so now the ratio, A12 of first AP : A12 of second AP
= 44/99 = 4/9 i.e. 4:9
I HOPE IT IS CORRECT AND HELPS U !!
jgxkgdkgdigd:
but answer is given 7:16
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