Question

Can someone solve this question paper please?​

Answer 1

$\huge\bold\green{Question \: 32}$

Find length of BC .

$\huge\bold\blue{answer \: 32}$

As we know :

$\bold\orange{according \: to \: pythagorus : } \\ \pink{ {base}^{2} + {perpendicular}^{2} = {hypotenuse}^{2} }$

let base be x

$( {x}^{2} ) + (12 {)}^{2} = ( {15})^{2}$

$( {x}^{2} ) + 144 = 225 \\ ( {x}^{2} ) = 225 - 144 \\ ({x}^{2} ) = 81 \\ \sqrt{x} = \sqrt{81} \\ x = 9cm$

$\huge\bold\green{Question \: 33}$

Show that ∆ ABD ≈ to ∆ ACD

$\huge\bold\blue{answer \: 33}$

ANGLE AB ≈ AC [ RIGHT ANGLES ]

AB≈ AC [ HYPOTENUSE ]

AD ≈ AD [ COMMON SIDE ]

hence ∆ ABD ≈ ACD BY RHS

$\huge\bold\green{Question \: 35}$

A circle of radius 2cm is cut out from a square piece of aluminium sheet of side 6cm . what is area of remaining sheet ?

$\huge\bold\blue{answer35}$

$\bold\orange{area \: of \: circle \: = {\pi \times( r)}^{2} } \\ area \: = 3.14 \times 2 \times 2 \\ area = 12.56 {cm}^{2} \\ \bold\pink{area \: of \: square = {(s)}^{2} } \\ area = 6 \times 6 \\ area = {36cm}^{2} \\ remaining \: part \: = \green{area \: of \: square - area \: of \: circle} \\ remaining \: part \: = 3 {6cm}^{2} - {12.56cm}^{2} \\ \: remaining \: part \: = 13. {44cm}^{2}$

$\huge\bold\green{Question \: 37}$

Write a statement for :

I) 4 added to X

ii) The number y multiplied by itself .

b) A circular pipe has radius 10cm . find the length of tape to wrap once around the tape .

$\huge\bold\blue{answer37 } \\ \\ i) \: 4 + x \\ ii) \: y \times y = {y}^{2}$

$\ \: \pink{length \: required = circumfrence \: of \: circle} \\ \bold\green{circumfrence \: of \: circle = 2\pi \: r } \\ circumfrence = 2 \times 3.14 \times 10 \\ circumfrence =62.8$

$\huge\bold\green{Question38}$

find the value if a= -2

$\huge\bold\green{answer} \: 38$

$2 { (- 2a)}^{2} - 4( - 2) + 5 \\ = > 2( - 2 \times - 2) + 5 \\ = > 2 \times 4 + 8 + 5 \\ = > 8 + 8 + 5 \\ = > 16 + 5 \\ = > 21$