can someone tell me whatis my mistake here
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Answered by
4
Hey there ....
cos 45°=
![\frac{1}{ \sqrt{2} } \frac{1}{ \sqrt{2} }](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+%5Csqrt%7B2%7D+%7D+)
Sec 30° =
![\frac{2}{ \sqrt{3} } \frac{2}{ \sqrt{3} }](https://tex.z-dn.net/?f=+%5Cfrac%7B2%7D%7B+%5Csqrt%7B3%7D+%7D+)
cosec 30° =
![2 2](https://tex.z-dn.net/?f=+2++)
so,
![\frac{ \frac{1}{ \sqrt{2} } }{ \frac{2}{ \sqrt{3} } \times 2} \frac{ \frac{1}{ \sqrt{2} } }{ \frac{2}{ \sqrt{3} } \times 2}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Cfrac%7B1%7D%7B+%5Csqrt%7B2%7D+%7D+%7D%7B+%5Cfrac%7B2%7D%7B+%5Csqrt%7B3%7D+%7D+%5Ctimes+2%7D+)
Root 3 / 4 root 2
Hope it helps you
cos 45°=
Sec 30° =
cosec 30° =
so,
Root 3 / 4 root 2
Hope it helps you
mae15:
cosec 30 is 2
Answered by
0
Answer:
3 root 2 - root 6/8
Step-by-step explanation:
(1/root2) / (2/root3 + 2)
= (1/root2) / (2+ 2root3)/root 3
= 1/root2 ☓ root 3/ (2 + 2 root 3)
= (root3) / 2 root 2 + 2 root 6
Rationalize :
We get
(root3) (2root 2 - 2 root 6)/(2root2)^2-(2root6)^2
= (2root6 - 2 root 18)/8 - 24
= 2 root 6 - 2 ☓ 3 root 2/ - 16
= 2root6 - 6root2/-16
Dividing by 2 :
➡️ root6 - 3root2/ - 8
Or,
Multiply by - 1 in numerator and denominator :
We get :
3root2 - root 6/8
This is the ans.
For more clarity refer to pic.
Hope this helps you
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