Can somone pls answer this question for me?plssss......q.no.12..the highlighted one
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i think E = 0 and B = 0 because charge doesnt move anywhere (zero gravity)
or E = 0 and B not equal 0
in the case of B is in the direction of velocity of charge and doesnt experience any force
or E = 0 and B not equal 0
in the case of B is in the direction of velocity of charge and doesnt experience any force
london2023:
Yah frnd,I 've rechecked it...but 'am still confused
but i explain in detail
Okh frnd,thnk u so much
welcome
Sorry to disturb u frnd...but will ya' be able to manage to explain the concepts a little bit early......actually its a bit urgent
i see
but i dont explian in a efficient way but writing comments
u can see the book and easily u understand
Thnk u so much once again frnd.Bye and take care
welcome and bye
Answered by
1
Hello there
The answer of the question is (a) and (c)
Let's first discuss case a
Since there is Electric field E=0 and magnetic field B=0.
The total force on a charge particle is given
by F=qE+ qv xB
since E=0 and B=0
Hence F=0
Now
Let's first discuss case c
as F=qE+qv x B
the net force can be zero if electric and magnetic force are both equal to each other in magnitude and opposite in direction.
That means qE= -qv x B
In this case neither E nor B is zero but still the net Force is zero.
Thank you
The answer of the question is (a) and (c)
Let's first discuss case a
Since there is Electric field E=0 and magnetic field B=0.
The total force on a charge particle is given
by F=qE+ qv xB
since E=0 and B=0
Hence F=0
Now
Let's first discuss case c
as F=qE+qv x B
the net force can be zero if electric and magnetic force are both equal to each other in magnitude and opposite in direction.
That means qE= -qv x B
In this case neither E nor B is zero but still the net Force is zero.
Thank you
If you would like to show some appreciation please mark it as brainliest.Thank you
Thnk u so much frnd
Mention not
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