Can the sum of first n−1 terms of an AS be 5n2+2n−7.Why?
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hey mate, here's the answer
given condition, 5n^2+2n-7
(5n^2+5n)(-7n-7)
5n(n+1)-7(n+1)
(5n-7)(n+1)
n=7/5,n=-1
therefore, yes it can be
given condition, 5n^2+2n-7
(5n^2+5n)(-7n-7)
5n(n+1)-7(n+1)
(5n-7)(n+1)
n=7/5,n=-1
therefore, yes it can be
joshual88:
thanks
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