can the sum of n^th terms in AP is n^2 + 13n.justify your answer
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Solution:Let us assume that n^{th} term of an AP= n^2 +1
First term (a_1)=1^2+1=1+1=2
2^{nd}term(a_2)=2^2+1=4+1=5
3^{rd}term (a_3)=3^2+1=9+1=10
{Common difference} (d)= Difference between any two consecutive terms of an AP}
So,d=2^{nd} term
-First term= 3^{rd}term-2^{nd} term
d=5-2=10-5
d=3=2
But 3 ≠ 2
{ It is contradicting our assumption}
therefore n^{th} term of an AP can't be (n^2 +1)
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