can two no. have 16 their HCF & 324 as their LCM? give reason?
Answers
Answered by
4
heya mate !!
for verification u should divide the 324 by 16 if it completely divides the no. than IT will but if not than no not the factor.
hence it don't divide completely . so , it is not possible .
cause we know hcf is the factor of LCM
hope that helps !!
@ himanshu Jha
for verification u should divide the 324 by 16 if it completely divides the no. than IT will but if not than no not the factor.
hence it don't divide completely . so , it is not possible .
cause we know hcf is the factor of LCM
hope that helps !!
@ himanshu Jha
Answered by
3
if you want the two numbers to be integers,then the answer is NO.
since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.
Since,
product of LCM and HCF = product of the two numbers
18X380 = 18aX18b
=>18ab = 380
=> 9ab =190
Since 190 is not divisible by 9,a and b be can’t have integer values. so, there are no such number.
since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.
Since,
product of LCM and HCF = product of the two numbers
18X380 = 18aX18b
=>18ab = 380
=> 9ab =190
Since 190 is not divisible by 9,a and b be can’t have integer values. so, there are no such number.
harshmaster:
please brainlieast me
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