can two no. have 18 as their HCF and 380 as their LCM?given reason
Answers
Answered by
1
if you want the two numbers to be integers,then the answer is NO.
since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.
Since,
product of LCM and HCF = product of the two numbers
18X380 = 18aX18b
=>18ab = 380
=> 9ab =190
Since 190 is not divisible by 9,a and b be can’t have integer values. So there are no such number.
Similar questions