Can two numbers have 12 as their HCF and 512 their LCM? Justify your answer.
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HCF = 12
LCM = 512
a×b=HCF×LCM
let the numbers are 12a, and 12b say
LCM of 12a and 12b =12ab
12ab=512
ab=512/12
a and b are not integers
LCM = 512
a×b=HCF×LCM
let the numbers are 12a, and 12b say
LCM of 12a and 12b =12ab
12ab=512
ab=512/12
a and b are not integers
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