Math, asked by lakshit6, 1 year ago

can two numbers have 18 as their HCF and 380 as their LCM?give resion

Answers

Answered by Anonymous

Hey mate...

No ..it is not true cause HCF must be a factor of LCM...but 18 is not a factor of 380..

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saniya2326: if you want the two numbers to be integers,then the answer is NO.

since 18 is their HCF let the two nos. be 18*a and 18*b where a and b be are some positive integers.

Since,

product of LCM and HCF = product of the two numbers

18X380 = 18aX18b

=>18ab = 380

=> 9ab =190

Since 190 is not divisible by 9,a and b be can’t have integer values. So there are no such number.

Answered by Anonymous

Hi friend,

Here is your answer,
_____________________________________________________________

HCF of two numbers should be divisible by their by their LCM.

Let the numbers be a and b.
According to question,
HCF(a,b) = 18
LCM(a,b) = 380

³⁸⁰/₁₈ = 21.111...

18 is not divisible by 380 so no two numbers can have 18 and 380 as their HCF and LCM respectively.
_____________________________________________________________

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