can u answer this 2 question
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In question no. 5),BA//CE and BD act as transversal
So, angle ABC = ECD. (corresponding angles)
and since in triangle ABC, AB = AC
=> angle ABC=ACB. ( angle opposite to equal sides are equal)
=> angle ABC = ACB=70°
=> angle( ABC + ACB + BAC) = 180°
=> 2× 70° + angle A = 180°
=> angle A = 180°- 140°
So, angle A = 40°
Thus, B is the correct option. Ans
In question no.6)
In triangle ABC, since AC = BC
=> angle CAB= ABC
So, angle(ABC +CAB+ ACB)= 180°
=> 2angle ABC +50° = 180°
=> 2(ABC) = 180-50 = 130°
÷> angle ABC= 65°....(1)
Clearly, BE//CA andFC act as a transversal.
So, Angle EBC = angle ACD= 130°
=> angle EBC= angle(EBA+ABC)
=> 130 = (n + 65°). [using (1)]
=> 130 - 65= n
=> n= 65°
So, measure of angle n is 65° •
Thus,1 is the correct option. Ans
So, angle ABC = ECD. (corresponding angles)
and since in triangle ABC, AB = AC
=> angle ABC=ACB. ( angle opposite to equal sides are equal)
=> angle ABC = ACB=70°
=> angle( ABC + ACB + BAC) = 180°
=> 2× 70° + angle A = 180°
=> angle A = 180°- 140°
So, angle A = 40°
Thus, B is the correct option. Ans
In question no.6)
In triangle ABC, since AC = BC
=> angle CAB= ABC
So, angle(ABC +CAB+ ACB)= 180°
=> 2angle ABC +50° = 180°
=> 2(ABC) = 180-50 = 130°
÷> angle ABC= 65°....(1)
Clearly, BE//CA andFC act as a transversal.
So, Angle EBC = angle ACD= 130°
=> angle EBC= angle(EBA+ABC)
=> 130 = (n + 65°). [using (1)]
=> 130 - 65= n
=> n= 65°
So, measure of angle n is 65° •
Thus,1 is the correct option. Ans
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