can u answer this question fast plzzzzzz
u will get 20 ptssss
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as the triangles PAB and RAB are on the same base and between parallel lines ,there areas are equal(based on the theorem)
the area of a llgm is twice the area of the triangle whose base lie on the same line and lie between two parallel lines(based on a theorem)
so ar(ABCD)=2ar(PAB)=2*8 cm sq=16 cm sq
the area of a llgm is twice the area of the triangle whose base lie on the same line and lie between two parallel lines(based on a theorem)
so ar(ABCD)=2ar(PAB)=2*8 cm sq=16 cm sq
varshuu:
i am having xam 2moro
the paper has leaked this question is for 3mrks .....thank u for helping me to gain 3 mrks
all the best for ur xam
tq
thanks for a question whch i know
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madhu
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For first one by the theorem " triangles between same base and same parallels have equal area".....
There is also another formula saying that "if a parallelogram and a triangle lie between the same base and same parallel then the area of triangle is half the area of parallelogram".....
So area of parallelogram ABCD=8 x 2=16cm^2
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