The diaension of a cubiod are in the ratio of 1:2:3 and its total surface area is 88m2 find the dimensions
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Let length breadth and height be=1x:2x:3x
Surface Area of cuboid=2(lb+bh+hl)
88=(x*2x+2x*3x+3x*x)
2x²+6x²+3x²=44
x²=44/11
x=2 cm
put value of x and u will get the dimensions.
Surface Area of cuboid=2(lb+bh+hl)
88=(x*2x+2x*3x+3x*x)
2x²+6x²+3x²=44
x²=44/11
x=2 cm
put value of x and u will get the dimensions.
Answered by
1
The ratio of sides -
1 : 2 : 3
Let the common multiple be 'x'.
So, the sides will be
x , 2x and 3x
Now, TSA of cuboid =
2(lb + bh + hl)
2(2x² + 6x² + 3x²)
22x²
Now,
88 = 22x²
x² = 4
x = √4 = 2
Therefore the dimensions of the cuboid are -
x = 2 units
2x = 2 × 2 = 4 units
3x = 3 × 2 = 6 units
1 : 2 : 3
Let the common multiple be 'x'.
So, the sides will be
x , 2x and 3x
Now, TSA of cuboid =
2(lb + bh + hl)
2(2x² + 6x² + 3x²)
22x²
Now,
88 = 22x²
x² = 4
x = √4 = 2
Therefore the dimensions of the cuboid are -
x = 2 units
2x = 2 × 2 = 4 units
3x = 3 × 2 = 6 units
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