Math, asked by simpleboy36, 6 months ago

Can u guys answer question 7 pls real quick

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Answered by adityadhall007
0

Answer:

HELLO DEAR,

YOU CAN ALL THESE ANS. ON WWW.CBSE.IN OF ALL CLASSES AND SUBJECT

HOPE YOU FIND IT!!!!!!!!

Answered by grizzlyb753697
0

Step-by-step explanation:

1 \div \sqrt{3} -\sqrt{2} \\  = (1  \div  \sqrt{3} -  \sqrt{2}) \times  \sqrt{3}   +  \sqrt{2}  \div  \sqrt{3}  +  \sqrt{2}  \\  =  \sqrt{3}   +   \sqrt{2} \div  (\sqrt{3}   -   \sqrt{2} ) \times  \sqrt{3}  +  \sqrt{2}  \\  =  \sqrt{3}  +  \sqrt{2}  \div ( \sqrt{3})^{2}  - ( \sqrt{2} ) ^{2}  \\  =  \sqrt{3 }  +  \sqrt{2}  \div 3 - 2 \\  =  \sqrt{3}  +  \sqrt{2}  \div 1 \\  =  \sqrt{3}  +  \sqrt{2}

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