Question

can u help me in solving this prlmb

Answer 1

EF||AD
EF||AB
BY BP THEOREM,
$\frac{fc}{af} \: = \frac{ce}{eb}$
let it be eq 1

similarly,DE||AC
$\frac{ce}{eb} = \frac{ad}{db}$
from 1,
$\frac{fc}{af} = \frac{ad}{db}$
therefore proved