can u please explain the para in image above
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Barium sulphate is filtered and as a result of this filtration a new compound H₂O₂ is obtained/formed.
The sulphuric acid has a disadvantage as it causes the decomposition of of hydrogenperoxide. to avoid this acids like orthophosphuric acid, carbonic acids are preferred. and when barium peroxide is treated with orthophosphoric acid the result formed gives a precipitate or left over pieces of barium phosphate and H₂O₂ which goes into the solution
3BaO₂+2H₃PO-->Ba₃(PO₄)₂+3H₂O₂ppm
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