Question

can u please explain the para in image above​

Answer 1

Answer:

Barium sulphate is  filtered and as a result of this filtration a new compound H₂O₂ is obtained/formed.

The sulphuric acid has a disadvantage  as it causes the decomposition of of hydrogenperoxide. to avoid this acids like orthophosphuric acid, carbonic acids are preferred. and when barium peroxide  is treated with orthophosphoric acid the result formed gives a precipitate or left over pieces of barium phosphate and H₂O₂ which goes into the solution

3BaO₂+2H₃PO-->Ba₃(PO₄)₂+3H₂O₂ppm

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