Question

find the value of k . given the distance of point (2,k) and (4,3) is a. ?​

Answer 1

Step-by-step explanation:

(2,k) = (x1,y1)

(4,3) = (x2,y2)

distance = √ ( x2-x1)^2 + (y2-y1)^2

a = √ (2-k)^2 + 1^2

a^2 = 4 + k^2 - 8k

$k \: = \frac{ {a}^{2} - 4 - {k}^{2} }{ - 8}$

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Hope it helps you buddy

Answer 2

Step-by-step explanation:

we have two points,

A(2,k) and B(4,3)

acc. to question,

√{(4-2)²+(3-k)²} = a

4 +9+k²-6k = a²

k²-6k+13 = a²

k = {-(-6)+-√(36-52)}/2 = a²

so there is no real value of k