Question

can u please help me out​

Answer 1

Given that :

Highest frequency = 20

So, the Modal class will be 20-30

Here, Frequency of Modal class = 20

Lower limit of Modal class = 20

Frequency of the class preceding the modal class = 12

Frequency of the class succeeding the modal class = 10

Size of class interval = 10

As we know that from the formula of Mode :

$Mode = l + ( \frac{ f_{1} - f_{0}}{2f_{1} -f_{0} - f_{2} } ) \times h$

Now, on putting the value in the formula

$Mode = 20 + ( \frac{20 - 12}{2 \times 20 - 12 - 10} ) \times 10 \\ \\ = > Mode = 20 +( \frac{8}{40 - 22} ) \times 10 \\ \\ = > Mode = 20 + \frac{8}{18} \times 10 \\ \\ = > Mode = 20 + \frac{80}{18} \\ \\ = > Mode = \frac{360 + 80}{18} \\ \\ = > Mode = \frac{440}{18} \\ \\ = > Mode = 24.44$

So, the mode of the given frequency will be 24.44 ✔✔

_________________________________

Hope it helps ☺