Question

Can u please solve the 10 & 11 question...class9...polynomials

Answer 1

10)

factor of

${x}^{2} + 2x - 3 \\ {x}^{2} - 1x + 3x - 3 = 0 \\ x(x - 1) + 3(x - 1) = 0 \\ (x - 1)(x + 3) = 0\\ x - 1 = 0 \: \: \: x + 3 = 0 \\ x = - 1 \: \: \: \: \: \: x = - 3 \\ substitute \: - 3 \: in \: {x}^{4} + 2 {x}^{3} - 2 {x}^{2} + 2x - 3 \\ { - 3}^{4} + 2( { - 3}^{3} ) - 2( { - 3}^{2} ) + 2( - 3) - 3 \\ 81 - 54 - 18 - 6 - 3 \\ 81 - 81 = 0$

therefore it divides exactly