can u plzzzzzz solve it for me plzzz
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snehalodi:
noo we have to find area of ABCD
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Hey dear,
we can find out the area of triangle ADB
so height for this triangle wud be equal to the height of trapezium.
so we get height = 12cm.
now we can easily get to CD=7cm
and we know area of trapezium =1/2*(AB+CD)*HEIGHT
NOW,1/2*(25+7)*12 = 192 cm.
how to get CD=7 cm
when we will drop two perpendicular lines from D to AB as point E and from C to AB as point F.
So,we can see that EF = CD (as the line drawns were perpendicular)
Now In triangleADE,
We know AD=15 and DE=12
So we can easily find AE = 9
Similarly from triangleBCF,
we will get BF = 9cm
therefore,EF = AB -(AE+BF) = 25 - 18 =7cm.
Hope it Helpful to uh.. :)
we can find out the area of triangle ADB
so height for this triangle wud be equal to the height of trapezium.
so we get height = 12cm.
now we can easily get to CD=7cm
and we know area of trapezium =1/2*(AB+CD)*HEIGHT
NOW,1/2*(25+7)*12 = 192 cm.
how to get CD=7 cm
when we will drop two perpendicular lines from D to AB as point E and from C to AB as point F.
So,we can see that EF = CD (as the line drawns were perpendicular)
Now In triangleADE,
We know AD=15 and DE=12
So we can easily find AE = 9
Similarly from triangleBCF,
we will get BF = 9cm
therefore,EF = AB -(AE+BF) = 25 - 18 =7cm.
Hope it Helpful to uh.. :)
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