rationalise the denominator of 2/root3+root 5
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for rationalisation we will multiply and divide by √3-5
= (2/(√3+5))*((√3-5)/(√3-5))
= (2√3-10)/(√3+5)(√3-5)
used identity is
(a+b)(a-b) = a²-b²
= 2√3-10/(3-25)
= 2(5-√3)/22
= 5-√3/11
= (2/(√3+5))*((√3-5)/(√3-5))
= (2√3-10)/(√3+5)(√3-5)
used identity is
(a+b)(a-b) = a²-b²
= 2√3-10/(3-25)
= 2(5-√3)/22
= 5-√3/11
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