Question

rationalise the denominator of 2/root3+root 5

Answer 1

for rationalisation we will multiply and divide by √3-5

= (2/(√3+5))*((√3-5)/(√3-5))

= (2√3-10)/(√3+5)(√3-5)
used identity is

(a+b)(a-b) = a²-b²

= 2√3-10/(3-25)

= 2(5-√3)/22

= 5-√3/11

Answer 2

I hope it may help u ☺️ ☺️