Question

Can u solve it please .........???

Answer 1

Answer:

angle OEA = 90° [AB is a Tangent to the circle]

therefore OAE is a right angle triangle

therefore,

$ae ^{2} = {ao}^{2} - {oe}^{2} \\ \: \: \: \: \: \: \: = {8}^{2} - {4}^{2} \\ \: \: \: \: \: \: \: = 64 - 16 \\ \: \: \: \: \: \: \: = 48 \\ ae \: = 4 \sqrt{3}$

Therefore AE is :

$4 \sqrt{3}$

That was quite easy though.....

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