Math, asked by anirudha20, 1 year ago

can u solve the question of 4 no

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Answers

Answered by inhumandrowsey
1

CI = Principal (1 + r/100)^t - Principal

Amount = CI + principal

(i) CI = 46875 (1 + 4/100)^1 - 46875

= 46875 (1 + 1/25) - 46875

= 46875 * 26/25 - 46875

= 1218750/25 - 46875

= 48750 - 46875

= 1875

(ii) Amount at the end of second year = 46875 (1 + 4/100)²

= 46875 (26/25)²

= 46875 * 26/25 * 26/25

= 75 * 26 * 26 = 50700

interest = 50700 - 46875 = 3825

(iii) CI = 46875 (1 + 4/100)³

= 46875 * 26/25 * 26/25 * 26/25 - 46875

= 3 * 26 * 26 * 26 - 46875

= 52728 - 46875

= 5853

5853 is the interest for all the three years

so interest for the 3rd year will be 5853 - 3825 = 2028

so we get 2028 as the interest for 3rd year


inhumandrowsey: ^ is the symbol for power
anirudha20: how I will refresh
inhumandrowsey: reload your page
anirudha20: if i do not write the (1+r7100)and ^ this
inhumandrowsey: it is r/100
anirudha20: it will be wrong or not
anirudha20: yes yes whatever
inhumandrowsey: it will be fine, coz on paper you dont have to draw that symbol coz you can write power there
anirudha20: i'm posting new question
inhumandrowsey: okay
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