Math, asked by vaishnavi9542, 10 months ago

can u solve this log2+4log5 in single logarithms

Answers

Answered by ayushisingh3478

0

Answer:

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Answered by tejamonster

0

Answer:log1250

Step-by-step explanation:log2+4log5

=log2+log5^4 (since m log a base n=loga^m base n)

=log2+ log625 ( since 5^4=625)

=log 2×log 625 (since loga+logb =loga×b)

=log1250

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