Question

can u solve this question plz​

Answer 1

$\underline{ \underline{ { \huge{ \mathfrak{R}}} \mathfrak{equired} \: \: \: { \huge{ \mathfrak{ A}}} \mathfrak{nswer :-}}}$

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$: \longrightarrow \red {\sf{ \: sin² \: 30° \: cos²45° \: + 4 \: {tan}^{2} \: {30}° + \dfrac{1}{2} \: {sin}^{2} \: 90 ° - 2 \: {cos}^{2} 90 ° + \frac{1}{24} \: {cos}^{2} 0° }} \\ \\ \rightarrow{\blue {\sf{ \: ( { \frac{1}{2} )}^{2} ( { \frac{1}{ \sqrt{2} } )}^{2} + 4 \: ( { \frac{1}{ \sqrt{3} } )}^{2} + \frac{1}{2} \: ( {1})^{2} - 2 \: ( {0})^{2} + \frac{1}{24} \: ( {1)}^{2} }}} \\ \\ \rightarrow \blue{ \sf{ \: \frac{1}{4} \: \times \: \frac{1}{2} + 4 \times \frac{1}{3} + \frac{1}{2} - 0 + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \: \frac{1}{8} + \frac{4}{3} + \frac{1}{2} + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \: \frac{3 + 32}{24} + \frac{1}{2} + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \: \frac{35}{24} + \frac{1}{2} + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \: \frac{35 + 12}{24} + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \: \frac{47}{24} + \frac{1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \frac{47 + 1}{24} }} \\ \\ \rightarrow \blue{ \sf{ \frac{ \cancel{48} ^{2} }{ \cancel{24}} }} \implies \boxed{ \sf{2 \: \: \: ...ans}}$

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Note :-

In these types of sums you need to just put the standard values of the given trigonometry ratios and simplify it further..

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@MissSolitary✌️