Question

Can u tell me the answer for 16th question with explanation??

Answer 1

follow these steps :-
Step 1:   Percentage of the elements present 
              Carbon               Hydrogen                        Chlorine         
               10.06                     0.84                            89.10
Step 2:  Dividing the percentage compositions by the respective atomic weights of the elements                                                           
             0.84                           0.84                              2.51
Step 3:  Dividing each value in step 2 by the smallest number among them to get simple atomic ratio                                                             
Step 4:  Ratio of the atoms present in the molecule
             C  : H  : Cl             
              1  :  1  :   3             
 The empirical formula of the compound C₁H₁Cl₃ or CHCl₃

Answer 2

Carbon= 10.06 g 
Hydrogen = 0.84 g
Chlorine = 89.10 g

Find the no of moles

For Carbon, n = 10.06/ 12 = 0.837≈0.84 moles
For Hydrogen , n = 0.84/1 = 0.84 moles
For Chlorine n = 89.10/35.5 = 2.5 moles

Now divide all elements masses with the smallest number of moles

Carbon = 0.84/0.84 = 1
Hydrogen = 0.84/0.84 = 1 
Chlorine = 2.5/0.84 = 2.976≈3 

So, Emperical Formula = CHCl3