Question

can we find the area of Major sector either way!!

( please don't answer yes, if u Don't know for the sake of points)​

Answer 1

Both are correct.

But You must be knowing that second method is faster.

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$Major \: sector = \pi {r}^{2} - \frac{ \theta}{360} \pi {r}^{2} \\ \\ = \bigg(1 - \frac{ \theta}{360}\bigg) \pi {r}^{2} \\ \\ = \bigg( \frac{360}{360} - \frac{ \theta}{360} \bigg) \pi {r}^{2} \\ \\ = \bigg( \frac{ 360 - \theta}{360} \bigg)\pi {r}^{2}$

Answer 2

Answer:-

Yes, offcourse:-

Sector

=πr 2− 360θπr 2

=(1− 360θ )πr2

=( 360/360 − 360θ )πr

2=( 360360−θ )πr 2