Can we take four angle of quadrilateral in ap a-3d,a-d,a+d,a+3d
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The quadrilateral has 4 angles and their values
are in AP, the first being unknown but the CD is
20 degrees. The equation for the sum of an AP is
Sn = (n/2)[2a+(n-1)d]... (1)
Here we do not the first value, a,, but we know
the rest. Sn = 360, n = 4 and d = 20. Let us
substitute the values in the equation (1), to get
360 = (4/2)[2a +(4-1)*20], or
360 = 2[2a + 3*20]. or
180 = 2a + 60, or
120 =a, or
a=60.
Hence the four angles are: 60, 80, 100, 120
degrees.
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