Physics, asked by Gauravkanaujiya3251, 1 month ago

Can we use colligative properties i=1+(n-1) dissociation in boards?

Answers

Answered by shahidaahmed12111980
0

Answer:

yes you can use

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Answered by mujahidk2005
0

Answer:

Consider one mole of a substance An (like an electrolyte), which on dissociation in the solution gives n number of particles A. Let α be the degree of dissociation at equilibrium. Then, the dissociation equilibrium can be represented as,

An⇔nA

At startAt equilibrium11−α0nαmolemole

At start, let the number of moles of An (or particles) be 1.

At equilibrium

The total number of moles of particles =1−α+nα

=1+nα−α

=1+α(n−1)

Theoretical colligative properties are due to 1 mole while the observed colligative properties are due to 1+α(n−1) moles of particles in the solution.

The van't Hoff factor i, will be,

i=Observed colligative propertyTheoretical colligative property

Now,

Colligative property α Number of particels in the solution.

∴i=1+α(n−1)1

∴iˆ=1+α(n−1)

∴α(n−1)=iˆ−1

∴α=i−1(n−1)

This is the relation between degree of dissociation and van't Hoff factor i.

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