can (x-1) be the remainder on division of a polynomial p(x) by (x+3).Justify your answer.
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✔️By using Euclid's division algorithm we know that, a = b × q + r
Where,
⭐divident ( a ) = p ( x )
⭐Divisior ( b ) = ( x + 3 )
Here, we can see that degree of divisior = 1 ---i)
⭐Also, remainder or r ( x ) => ( x - 1 ) [ given ]
So, degree of remainder = 1 ------ ii)
So, equation i) = equation ii) so it is possible.
Hence, we can conclude that ( x - 1 ) is not a remainder of p ( x ).
______________________
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Hope it helps ☺️
✔️By using Euclid's division algorithm we know that, a = b × q + r
Where,
⭐divident ( a ) = p ( x )
⭐Divisior ( b ) = ( x + 3 )
Here, we can see that degree of divisior = 1 ---i)
⭐Also, remainder or r ( x ) => ( x - 1 ) [ given ]
So, degree of remainder = 1 ------ ii)
So, equation i) = equation ii) so it is possible.
Hence, we can conclude that ( x - 1 ) is not a remainder of p ( x ).
______________________
# ¢ ' $ #
Hope it helps ☺️
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