Question

find the height of the trapezium, the sum of the length of whose base is 39 cm and whose area is 65 CM square

Answer 1

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$<b > here we go.........$



$\frac{1}{2} \times 39 \times x = 65cm {}^{2}$



$39x = 65 \times 2$


$x = \frac{65 \times 2}{39} = 3.33cm$




Hope it helps you


$<marquee > prabhudutt$

Answer 2

$<b>Heya !$

Here's your answer !!


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Given :

In a trapezium,

Sum of length of bases = 39 cm

Area = 65 cm²

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To Find :

Height = ?

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Solution :

$\bf = > \: area \: = \: \frac{1}{2} \times \: ( \: sum \: of \: bases \: ) \: \times \: height \\ \\ = > \bf \: 65 \: = \: \frac{1}{2} \: \times \: 39 \: \times \: h \\ \\ = > \bf \: h \: = \: \frac{65 \: \times \: 2}{39} \\ \\ = > \bf \: h \: = \: 3.33 \: cm \:$

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Thanks !!