can you all solve these three questions
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1. Angle B and C will be 68
2.96degree
3.40degree
2.96degree
3.40degree
Answered by
1
1. IN TRIANGLE ABC
AB=AC
HENCE, ANGLE B=angleC=x. (say)
then
angleA +angleB +angleC=180°
(angl sum property of triangle)
2x=180-44
x=136/2=68
so the of angleB and angleC is 68°
2. In triangle PQR
angleR =angleQ=42° (PQ=QR)
then
angle p=180°-84°=96°
( by sum angle property of triangle)
3. since AB=AC
angleB=angleC=40°
AB=AC
HENCE, ANGLE B=angleC=x. (say)
then
angleA +angleB +angleC=180°
(angl sum property of triangle)
2x=180-44
x=136/2=68
so the of angleB and angleC is 68°
2. In triangle PQR
angleR =angleQ=42° (PQ=QR)
then
angle p=180°-84°=96°
( by sum angle property of triangle)
3. since AB=AC
angleB=angleC=40°
manikumar2:
hey the first one would be 68
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