Question

can you answer 5and 6...

Answer 1

5.

A + B + C = 180°

B + C = 180° - A

then,

tan(B + C /2)

=tan(90° - A/2)

=cotA/2

6.

Apply pythagoras theorem in triangle APR

AP² +AR² = PR²

6² + 8² = PR²

PR = 10 cm

now,

in triangle QPR

QP² + PR² = QR²

(24)² + (10)² = (26)²

576 + 100 = 676

676 = 676

Since, it satisfies the pythagoras theorem so it is a right triangle.

And QR is the greatest side so it is hypoteneus.

then,

angle P = 90°  (angle opposite to the hypoteneus)

Hope it helped you...

Answer 2

Answer:

A + B + C = 180°

B + C = 180° - A

then,

tan(B + C /2)

=tan(90° - A/2)

=cotA/2

6.

Apply pythagoras theorem in triangle APR

AP² +AR² = PR²

6² + 8² = PR²

PR = 10 cm

now,

in triangle QPR

QP² + PR² = QR²

(24)² + (10)² = (26)²

576 + 100 = 676

676 = 676

Since, it satisfies the pythagoras theorem so it is a right triangle.

And QR is the greatest side so it is hypoteneus.

then,

angle P = 90°  (angle opposite to the hypoteneus)

Hope it helped you...