Question

can you answer it?
using algebraic identity​

Answer 1

Answer:

Given:-

a+b+c=9

ab+bc+ca=23

Identity:-

$( {a + b +c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

Solution:-

$( {a + b +c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

${9}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

$81 = {a}^{2} + {b}^{2} + {c}^{2} + 2(23)$

${a}^{2} + {b}^{2} + {c}^{2} + 46 = 81$

${a}^{2} + {b}^{2} + {c}^{2} = 81 - 46$

${a}^{2} + {b}^{2} + {c}^{2} = 35$

Answer 2

Answer:

a^2+b^2+c^2= (a+b+c)^2-2(ab+bc+ca)

=9^2-2*23

=81-46

=35