can you answer this?
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3) may be ur answer
hope it help
hope it help
shumailashuaib:
yes plz
see E (equitorial)=kp/(r2+a2)^3÷2
E equi= 15k×10^-9÷125
nw E axial=2kpr (r2-a2)^2
so E axial =120×10^-9÷49
k it was right.... thanks
divide eq 2 by eq 1
i got it
1000÷49 is the answer (1)
thanks
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