Question

can you answer this?​

Answer 1

Answer:

diameter =4.2m

radius =2.1m

$csa \: = 2\pi \: rh$

$csa = 2 \times \frac{22}{7} \times 2.1 \times 5 \\ = 66 {m}^{2}$

$waste \: steel = \frac{1}{12} \times 93.72 = 7.81 {m}^{2}$

actual steel used = 93.72 - 7.81=85.91