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k ) angle OAB and angle ABO are equal because it is isoscles triangle .therefore the angles are 30 and 30 and therfore the angle AOB is 180-30-30=120.
in triangle AOC .
Angel OCB = Angle OAC.
THEREFORE angles are 20 and 20.
and thus the angle AOCis 180-20-20= 140.
angle BOC (inside one) os 120+140=260.
and we know that a complete angle is 360.
therefore 360-260= 100.
x value is 100.
in triangle AOC .
Angel OCB = Angle OAC.
THEREFORE angles are 20 and 20.
and thus the angle AOCis 180-20-20= 140.
angle BOC (inside one) os 120+140=260.
and we know that a complete angle is 360.
therefore 360-260= 100.
x value is 100.
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First Question:-
Triangle ABO is an isosceles triangle so the angle AOB = angle ABO = 30°
So angle AOB = 180°-60° = 120°
Triangle ACO is an isosceles triangle so the angle AOC = angle ACO = 20°
So angle AOC = 180°-40° = 140°
Angle x = 360°-(120° + 140°) = 360° - 260° = 100°
Second Question:-
Answer is in the photo below.
Hope this helps you if you like it please mark it Brainliest :D
Triangle ABO is an isosceles triangle so the angle AOB = angle ABO = 30°
So angle AOB = 180°-60° = 120°
Triangle ACO is an isosceles triangle so the angle AOC = angle ACO = 20°
So angle AOC = 180°-40° = 140°
Angle x = 360°-(120° + 140°) = 360° - 260° = 100°
Second Question:-
Answer is in the photo below.
Hope this helps you if you like it please mark it Brainliest :D
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