Math, asked by HarshalHere, 11 months ago

Can you Answer this question!

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Answered by snehadubey529
1

Let the numbers be a-d, a, a+d

Let d be the common difference

a-d+a+a+d=18

3a=18

a=18/3

a=6

(a-d)(a+d)=5d

a^2 - d^2 = 5d ( (a-b)(a+d)=a^2 -d^2 )

Put the value of 'a' in equation

(6)^2 -d^2 = 5d

36 - d^2 = 5d

0= d^2 +5d -36

d^2 +5d -36 =0

d^2 + 9d - 4d -36. (Splitting the middle term)

d(d+9)-4(d+9)

(d+9)(d-4)

d= -9

d= 4

d = 4

The terms are (6-4), 6, (6+4)

Terms= 2, 6, 10.

Hope it helps.

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