Question

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Answer 1

Step-by-step explanation:

The given points are A(−5,1), B(1,p) and C(4,−2)

We have (x1=−5,y1 =1),(x2=1,y2 =p) and (x3 =4,y3=−2)

The given points A,B and C are collinear

Therefore, x1(y2 −y3 )+x2 (y3 −y1 )+x3 (y1 −y2)=0

⇒(−5)⋅(p+2)+1⋅(−2−1)+4⋅(1−p)=0

⇒(−5p−10−3+4−4p)=0

⇒−9p=−9

⇒p=−1

Hence, p=−1

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