can you construct a triangle pqr with q r equal to 4 cm angle Q equal to 60 degrees and PQ - PR equal to 5 cm give reason
Answers
Answered by
8
We have to construct a triangle with the given data as-
Step-1: Draw the base line segment QR= 6 cm.
Step-2 : From Q, draw an angle ofusing compass, say ∠XQR.
Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.
Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.
Thus ΔPQR is the required triangle.

hope it may helps plz mark as brainliest
Step-1: Draw the base line segment QR= 6 cm.
Step-2 : From Q, draw an angle ofusing compass, say ∠XQR.
Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.
Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.
Thus ΔPQR is the required triangle.

hope it may helps plz mark as brainliest
uday147:
thanks can we get friends
Answered by
4
Answer:
No we cannot construct the triangle
For reason go to the preference
Attachments:
Similar questions