If alpha and beta are the zeroes of the polynomial p(x)=3x^2-4x-7, then form a quadratic polynomial whose zeroes are 1÷2 and 1÷beta
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3x²-4x-7=3x²+3x-7x-7
=3x(x+1)-7(x+1)
=(3x-7)(x+1)
the zeroes are -7/3 and -1
α=-7/3
β=-1
then the quadratic polynomial whose zeros are 1/α and 1/β is
sum of zeros= 1/ α + 1/β
=-10/7
product of zeros=1/α ×1/β
=3/7
then the resulting equation is
7x²+10x +3
I hope it helps u
plz brainliest
=3x(x+1)-7(x+1)
=(3x-7)(x+1)
the zeroes are -7/3 and -1
α=-7/3
β=-1
then the quadratic polynomial whose zeros are 1/α and 1/β is
sum of zeros= 1/ α + 1/β
=-10/7
product of zeros=1/α ×1/β
=3/7
then the resulting equation is
7x²+10x +3
I hope it helps u
plz brainliest
tejasri2:
will u ask some more
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2
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